cos(t)+sin(2t)

解一个三角函数方程a*cos(t)=b*sin(t)+2*sin(t)*cos(t)a,b,t,均为实数结果要求用a,b显式表达出t解一个三角函数方程a*cos(t)=b*sin(t)+2*sin(t)*cos(t)a,b,t,均为实数结果

求sin^2(t)*cos^4(t)dt的不定积分求sin^2(t)*cos^4(t)dt的不定积分求sin^2(t)*cos^4(t)dt的不定积分答：∫(sint)^2*(cost)^4dt=∫(sintcost)^2*(cost)^2

-2sin2t/cost为什么等于-4sint-2sin2t/cost为什么等于-4sint-2sin2t/cost为什么等于-4sint-2sin2t/cost=sintcost*sintcostsintcost=sin2t/2二倍角公式

sin(ωt)/cos(ωt)=sin(ωt)/sin(ωt+π/2)=e^(-j.π/2)=-j对么?sin(ωt)/cos(ωt)=sin(ωt)/sin(ωt+π/2)=e-j.π/2=cos(-π/2)+j.sin(-π/2)=-j

MatLab的程序问题ezplot(@(t)cos(t),@(t)sin(t),[0,2*pi])MatLab的程序问题ezplot(@(t)cos(t),@(t)sin(t),[0,2*pi])MatLab的程序问题ezplot(@(t)

(sint)/(1-cost)=(sint)/(1-cost)=(sint)/(1-cost)=全都用二倍角展开就行了tant\2绝对正解

cos(cos(t))-cos(sin(t))周期怎么求cos(cos(t))-cos(sin(t))周期怎么求cos(cos(t))-cos(sin(t))周期怎么求最小正周期为π,易证f(t+π）=f(t),且f(t)为偶函数

x=4*sin(2*pi*0.01*t).*sin(2*pi*3*t)+2*cos(pi*t*t/4);在matlab中怎样表达运行出现错误：Errorusing==>mtimesInnermatrixdimensionsmustagree

t=0:pi/100:10*pi;x=2*(cos(t)+t*sin(t));y=2*(sin(t)-t*cos(t));z=1.5*t;plot3(x,y,z)这个程序如何修改?老是提示Errorusing==>mtimesInnerma

e^(i*t^2)=cos(t^2)+i*sin(t^2)成立否?e^(i*t^2)=cos(t^2)+i*sin(t^2)成立否?e^(i*t^2)=cos(t^2)+i*sin(t^2)成立否?如果t^2∈R,那么e^(i*t^2)=c

急证：sint+cost-2/[1+tan^2(t/2)]急证：sint+cost-2/[1+tan^2(t/2)]急证：sint+cost-2/[1+tan^2(t/2)]sint=2tan(t/2)/[1+tan^2(t/2)]cost

ezsurf('u*sin(t)','u*cos(t)','100t/2816',[0,20,0,2])matlab画这个图我这个哪里错了?ezsurf('u*sin(t)','u*cos(t)','100t/2816',[0,20,0,2

tant/2怎么算出等于sint/（1+cost）.tant/2怎么算出等于sint/（1+cost）.tant/2怎么算出等于sint/（1+cost）.an2α=2tanα/[1-(tanα)^2]　　tan(1/2*α)=(sinα)

x=tan(t)sin(t)-cos(t)=?x=tan(t)sin(t)-cos(t)=?x=tan(t)sin(t)-cos(t)=?(sint-cost)²=sin²t+cos²t-2sintcost=1

帮忙解一道微积分,3tsin立方（2t-π）18tsin平方（2t-π）cos（2t-π）18tsin平方（2t-π）cos（2t-π）+3sin立方（2t-π）帮忙解一道微积分,3tsin立方（2t-π）18tsin平方（2t-π）cos

如何x(t)=cos(t)+asin(t)y(t)=sin(t)+bcos(t)expressingx(t)intheformAcos(t-α)和y(t)=Bsin(t-β)?、急在线等如何x(t)=cos(t)+asin(t)y(t)=s

cos^3+sin^3求化简设t=cos+sincos^3+sin^3求化简设t=cos+sincos^3+sin^3求化简设t=cos+sin(cosx+sinx)³=(cosx+sinx)²(cosx+sinx)=(

已知一个连续周期信号x(t)=1–cos(πt)+2sin(2πt)+cos(3πt),用DFT计算其频谱.已知一个连续周期信号x(t)=1–cos(πt)+2sin(2πt)+cos(3πt),用DFT计算其频谱.信号基频W＝π,周期T0

4√2sinωt+√2cosωt=√34[(4/√17)sinωt+(1/√17)cosωt]=√34(sinωtcosθ+cosωtsinθ)这是怎么分的,有什么技巧吗4√2sinωt+√2cosωt=√34[(4/√17)sinωt+(

求数学函数天才,出不来我死了,2sin(t)cos(t)+2sin(t)-cos(t)-1=0.这题答案是要在[0°,360°）求完整的求数学函数天才,出不来我死了,2sin(t)cos(t)+2sin(t)-cos(t)-1=0.这题答案