36+2y÷3=40y=?

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36+2y÷3=40y=?
y"=(y')^3+y'

y"=(y')^3+y'y"=(y')^3+y'y"=(y')^3+y'优化一下,y=arcsin(c1*e^x)+c2

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[(x+y)²-(x+y)(x+3y)-5y²]÷(2y) 其中x=-2,y=&

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(y^2)^4y-(-2y)^3y^6=

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y-31.5=25%y+(1-25%)y*40%y-31.5=0.25y+0.3y0.45y=31.5y=70这个方程计算过程对么?如果对,为什么对呢y-31.5=25%y+(1-25%)y*40%y-31.5=0.25y+0.3y0.45

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