已知数列{bn}满足:b1=b

已知数列{bn}满足b1=-1,b(n+1)=bn+(2n-1),求bn已知数列{bn}满足b1=-1,b(n+1)=bn+(2n-1),求bn已知数列{bn}满足b1=-1,b(n+1)=bn+(2

已知数列满足{bn}满足:b1=1,当n≥2时,bn=(2bn-1)/(bn-1+3),求bn其中,n-1都是b的下标已知数列{bn}满足:b1=1,当n≥2时,bn=(2bn-1)/(bn-1+3)

有关数列的数学题.已知数列{bn}满足b1=1,b2=3,b(n+2)=3b(n+1)-2bn.求证数列{b(n+1)-bn}是等比数列,求{bn}的通项公式.有关数列的数学题.已知数列{bn}满足b

已知数列{bn}满足b1=1,b(n+1)=2bn+2,求证{bn+2}是等比数列并指出其首项与公比已知数列{bn}满足b1=1,b(n+1)=2bn+2,求证{bn+2}是等比数列并指出其首项与公比

已知数列{bn}满足b1=1,b(n+1)=2bn+2,求证｛bn+2｝是等比数列,并指出其首相与公已知数列{bn}满足b1=1,b(n+1)=2bn+2,求证｛bn+2｝是等比数列,并指出其首相与公

已知数列{bn}满足b（n+1）=（1/2）bn+1/4,且b1=7/2,Tn为{bn}的前n项和1.求证：数列{bn-1/2}已知数列{bn}满足b（n+1）=（1/2）bn+1/4,且b1=7/2

已知数列{bn},b1=1,b(n+1)=2bn+1,求证数列{bn}为等比数列.已知数列{bn},b1=1,b(n+1)=2bn+1,求证数列{bn}为等比数列.已知数列{bn},b1=1,b(n+

已知数列{bn}满足b1=1,bn+1=2bn+2,求证：数列{bn+2}是等比数列,并指出首项与公比已知数列{bn}满足b1=1,bn+1=2bn+2,求证：数列{bn+2}是等比数列,并指出首项与

已知数列{bn}满足b1=1,bn+1=2bn+2,求证:数列{bn+2}是等比数列,并指出首项与公比已知数列{bn}满足b1=1,bn+1=2bn+2,求证:数列{bn+2}是等比数列,并指出首项与

已知等差数列｛an｝满足a2=3,a5=9,若数列｛bn｝满足b1=3,bn-1=a下标bn则bn为?已知等差数列｛an｝满足a2=3,a5=9,若数列｛bn｝满足b1=3,bn-1=a下标bn则bn

数列{bn}满足：b1=10,b(n+1)=100*bn^3,求数列{bn}的通项公式bn数列{bn}满足：b1=10,b(n+1)=100*bn^3,求数列{bn}的通项公式bn数列{bn}满足：b

已知等差数列,已知等差数列{an}满足a2=3,a5=9,若数列{bn}满足b1=3,b下标(n+1)=a下标bn,则{bn}的通项公式已知等差数列,已知等差数列{an}满足a2=3,a5=9,若数列

已知数列｛an｝前n项和为sn,且sn=2an-1,数列｛bn｝满足b1=2,bn+1=an+bn求an,b已知数列｛an｝前n项和为sn,且sn=2an-1,数列｛bn｝满足b1=2,bn+1=an

已知数列an的前n项和Sn=3^n-1,数列bn满足b1=1,bn=3b(n-1)+an,记数列bn的前n项和为Tn.求Tn已知数列an的前n项和Sn=3^n-1,数列bn满足b1=1,bn=3b(n

已知数列{bn}满足2b(n+1)=bn+1/bn,且bn>1,求{bn}通项公式已知数列{bn}满足2b(n+1)=bn+1/bn,且bn>1,求{bn}通项公式已知数列{bn}满足2b(n+1)=

已知数列｛an｝,｛bn｝满足：a1=1/4,an+bn=1,b（n+1）=bn/（1-an²）1）求b1,b2,b3的值已知数列｛an｝,｛bn｝满足：a1=1/4,an+bn=1,b（n

已知数列｛an}的前n项和为Sn＝2的n次方,数列｛bn｝满足b1＝－1,b(n+1)=bn+(2n-1),若Cn＝an乘bn的积再除以n已知数列｛an}的前n项和为Sn＝3的n次方，数列｛bn｝满足

已知等差数列{an}满足a2=3,a5=9,若数列{bn}满足b1=3,b下标(n+1)=a下标bn,则{bn}的通项公式已知等差数列{an}满足a2=3,a5=9,若数列{bn}满足b1=3,b下标

已知an=2n-1,数列｛bn｝满足：b1/2+b2/2^2+...+bn/2^n=an,求数列{bn}的前n项和Sn已知an=2n-1,数列｛bn｝满足：b1/2+b2/2^2+...+bn/2^n

已知数列{an}的前n项和为Sn=3的n次方,数列{bn}满足b1=-1,b(n+1)=bn+(2n-1),若Cn=a已知数列｛an}的前n项和为Sn＝3的n次方,数列｛bn｝满足b1＝－1,b(n+