2X^2+3X=27 X=?5x^3-3x^2-32x-12 因式分解

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2X^2+3X=27 X=?5x^3-3x^2-32x-12 因式分解

2X^2+3X=27 X=?5x^3-3x^2-32x-12 因式分解
2X^2+3X=27 X=?
5x^3-3x^2-32x-12 因式分解

2X^2+3X=27 X=?5x^3-3x^2-32x-12 因式分解
2X^2+3X=27
2X^2+3X-27=0
(X-3)(2X+9)=0
X=3,X=-9/2
5x^3-3x^2-32x-12
=(5x^3-15x^2)+(12x^2-36x)+(4x-12)
=5x^2(x-3)+12x(x-3)+4(x-3)
=(x-3)(5x^2+12x+4)
=(x-3)(5x+2)(x+2)

1)原式可化为（x-3)(2x+9)=0 => x=3或x=-9/2

第一个等于3

（2x+9）（x—3）

2X^2+3X=27
2X²+3X-27=0
2X²-6X+9X-27=0
2X(X-3)+9(X-3)=0
(X-3)(2X+9)=0
X=3或X=-9/2
5x^3-3x^2-32x-12
=5x³+10x²-13x²-26x-6x-12
=5x²(x+2)-13x(x+2)-6(x+2)
=(x+2)(5x²-13x-6)
=(x+2)(5x²-15x+2x-6)
=(x+2)[(5x(x-3)+2(x-3)]
=(x+2)(5x+2)(x-3)

2X^2+3X=27
X^2+3X-27=0
（X-3)(2X+9)=0
X1=3,X2=-9/2
5x^3-3x^2-32x-12
=5(x^3+2x^2)-13(x^2+2x)-6(x+2)
=5x^2(x+2)-13x(x+2)-6(x+2)
=(x+2)(5x^2-13x-6)
=(x+2)(5x+2)(x-3)

x(x+1)+(x+2)+(x+3)+(x+4)+(x+5) = 27求x x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少? x+x^2+x^3+x^4+x^5+.+x^27=? *-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X || (x-3/x-2)-(x-2/x-1)=(x-5/x4) -(x-4/x-3) 解方程x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6) x(x-2)-2x(x+1)-3x(x-5) 其中x=负½ x-2x+3x-4x+5x.+99x-100x=25求解 2x+3x+4x+5x+x+6x+7x=100 x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7 x=? 填九宫格帮帮忙.x x 6 x x 7 x x 98 x x x 3 x 1 x x 9 x x 6 x 5 x 3 x x x 3 x x x x 1 8x x x 9 x 1 x x x2 1 x x x x 6 x x x 6 x 7 x 3 x x 1 x x 9 x 2 x x x 47 x x 8 x x 5 x x x^5-2x^3+x=? 写过程x(x-1)+2x(x+1)-3x(2x-5)-x(3x-2)+2x(2-x)=-5x(x-2)-4 (X+1)X(X+2)X(X+3)=504 一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X 5x/(x-2)-2=3(x-2)/x 8x+3(x-2)=5x+(x-3) (X-5)(X+3)+(X-2)(X+4)=26