作业帮已知α,β属于（0,派/2)满足tan（α+β）=4tanβ,则tanα的最大值令dy/dx=[3(1+4x²)-24x²]/(1+4x²)²=(-12x²+3)/(1+4x²)²=3(1-4x²)/(1+4x²)²=0这一步怎么来的?
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/05 12:38:49
![已知α,β属于（0,派/2)满足tan（α+β）=4tanβ,则tanα的最大值令dy/dx=[3(1+4x²)-24x²]/(1+4x²)²=(-12x²+3)/(1+4x²)²=3(1-4x²)/(1+4x²)²=0这一步怎么来的?](/uploads/image/z/13331793-57-3.jpg?t=%E5%B7%B2%E7%9F%A5%CE%B1%2C%CE%B2%E5%B1%9E%E4%BA%8E%EF%BC%880%2C%E6%B4%BE%2F2%29%E6%BB%A1%E8%B6%B3tan%EF%BC%88%CE%B1%2B%CE%B2%EF%BC%89%3D4tan%CE%B2%2C%E5%88%99tan%CE%B1%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E4%BB%A4dy%2Fdx%3D%5B3%281%2B4x%26%23178%3B%29-24x%26%23178%3B%5D%2F%281%2B4x%26%23178%3B%29%26%23178%3B%3D%28-12x%26%23178%3B%2B3%29%2F%281%2B4x%26%23178%3B%29%26%23178%3B%3D3%281-4x%26%23178%3B%29%2F%281%2B4x%26%23178%3B%29%26%23178%3B%3D0%E8%BF%99%E4%B8%80%E6%AD%A5%E6%80%8E%E4%B9%88%E6%9D%A5%E7%9A%84%3F)
已知α,β属于（0,派/2)满足tan（α+β）=4tanβ,则tanα的最大值令dy/dx=[3(1+4x²)-24x²]/(1+4x²)²=(-12x²+3)/(1+4x²)²=3(1-4x²)/(1+4x²)²=0这一步怎么来的?
已知α,β属于（0,派/2)满足tan（α+β）=4tanβ,则tanα的最大值
令dy/dx=[3(1+4x²)-24x²]/(1+4x²)²=(-12x²+3)/(1+4x²)²=3(1-4x²)/(1+4x²)²=0
这一步怎么来的?
已知α,β属于（0,派/2)满足tan（α+β）=4tanβ,则tanα的最大值令dy/dx=[3(1+4x²)-24x²]/(1+4x²)²=(-12x²+3)/(1+4x²)²=3(1-4x²)/(1+4x²)²=0这一步怎么来的?
