把(x-y)看作一个整体,化解:5(x-y)+2(x-y)-4(x-y)= 3(x-y)把(x-y)看作一个整体,化解:5(x-y)+2(x-y)-4(x-y)=3(x-y)²-4(x-y)+7(x-y)-6(x-y)²=

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把(x-y)看作一个整体,化解:5(x-y)+2(x-y)-4(x-y)= 3(x-y)把(x-y)看作一个整体,化解:5(x-y)+2(x-y)-4(x-y)=3(x-y)²-4(x-y)+7(x-y)-6(x-y)²=

把(x-y)看作一个整体,化解:5(x-y)+2(x-y)-4(x-y)= 3(x-y)把(x-y)看作一个整体,化解:5(x-y)+2(x-y)-4(x-y)=3(x-y)²-4(x-y)+7(x-y)-6(x-y)²=
把(x-y)看作一个整体,化解:5(x-y)+2(x-y)-4(x-y)= 3(x-y)
把(x-y)看作一个整体,化解:
5(x-y)+2(x-y)-4(x-y)=
3(x-y)²-4(x-y)+7(x-y)-6(x-y)²=

把(x-y)看作一个整体,化解:5(x-y)+2(x-y)-4(x-y)= 3(x-y)把(x-y)看作一个整体,化解:5(x-y)+2(x-y)-4(x-y)=3(x-y)²-4(x-y)+7(x-y)-6(x-y)²=
重新发一次题过来,看清楚再发

说了是一个整体,所以我们可以直接算数字。。。相信我,没有错

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把(x-y)看作一个整体,化解:5(x-y)+2(x-y)-4(x-y)= 3(x-y)把(x-y)看作一个整体,化解:5(x-y)+2(x-y)-4(x-y)=3(x-y)²-4(x-y)+7(x-y)-6(x-y)²= 把x-y看作一个整体,合并同类项3(y-x)+2(x-y)+(y-x)-(x-y)谢谢了, 把(x+2y)或(a-b)分别看作一个整体来合并同类项. 把(x-y)看作一个整体,化简:(1)5(x-y)+2(x-y)-4(x-y);(2)3(x-y²-4(x-y)+7(x-y)-6(x-y) 把(x+y)、(x-y)看作整体,进行合并同类项;3(x-y)-4(x+y)+5(x-y)-(x+y). 把(x+y)、(x-y)看作整体,进行合并同类项:3(x-y)-4(x+y)+5(x-y)-(x+y). 把(x-y)看作一个整体,合并同类项,1/4(x-y)+2(x-y)的平方-3/4(x-y)-5(x-y)的平方. 正比例函数为y=kx;假如是x²,那么能不能把它看作一个整体? 把(x-y)看作一个整体,合并同类项:5(x-y)+2(x-y)-4(x-y)=______. 解方程 8x+19=51 把()看作一个整体 把(x-2y)看作一个整体,并合并下列中的同类项:2(x-2y)的平方-7(x-2y)的三次方+3(2y-x)的平方-(2y-x)的三次方 如果把(x-2y)看作一个整体,下列计算正确的是:( )A.(x-2y)²·(2y-x)³=(x-2y)^5B.(x-2y)²·(2y-x)²=-(x-2y)^4C.(x-2y)²·(2y-x)³(x-2y)²=(x-2y)^7D.(x-2y)²·(2y-x)³=-(x-2y)^5求详解 在方程组x+y=负3,1/2[x加y]-3y=5,中若把x+y看作一个整体,把x+y=负3代入1/2[x加y]-3y=5,解得y= ,所以x= 把x-y看成一个整体,合并同类项:5(x-y)+3(x-y)-7(x-y) 如果已知x+y=5,那么x+y+6=11;反之,如果已知x+y+6=11,那么x+y=5在以上运算中,体现了一种整体思想,这里的“x+y”可以看作一个“整体”。你能进行下面的计算吗?(1)已知x²-2x-5=0,那么2x 把x-y看做一个整体,合并同类项. 3(y-x)^2+2(x-y)+(y-x)-(x-y)^2 (2x+y-2z)² 将(2x+y)看作整体 把(X-Y)和(X+Y)各看作一个字母因式,合并同类项3(X+Y)²-(X-Y)+2(X+Y)²+(X-Y)-5(X-Y)²=2在后面是²,2在前面是与后面相乘.