(x-1)(x-2)分之1=(x-4)(x-5)分之1解方程

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(x-1)(x-2)分之1=(x-4)(x-5)分之1解方程

(x-1)(x-2)分之1=(x-4)(x-5)分之1解方程
(x-1)(x-2)分之1=(x-4)(x-5)分之1解方程

(x-1)(x-2)分之1=(x-4)(x-5)分之1解方程
1/{(x-1)(x-2)} = 1/{(x-4)(x-5)}
首先,分母不为零,∴x ≠ 1 , 2 , 4 ,5
通分:
(x-4)(x-5) = (x-1)(x-2)
x^2-9x+20=x^2-3x+2
6x=18
x=3

1/[(x-1)(x-2)]=1/[(x-4)(x-5)]
(x-4)(x-5) = (x-1)(x-2)
x^2-9x+20 = x^2-3x+2
6x= 18
x=3