已知x²-10x+25+|y-3|=0,求2xy+xy分之x²+x的值

已知x²-10x+25+|y-3|=0,求2xy+xy分之x²+x的值
已知x²-10x+25+|y-3|=0,求2xy+xy分之x²+x的值

已知x²-10x+25+|y-3|=0,求2xy+xy分之x²+x的值
x²-10x+25+|y-3|=0
(x-5)²+|y-3|=0
所以x=5,y=3
代入计算即可

x²-10x+25+|y-3|=0 (x-5)²+|y-3|=0
∴x-5=0
y-3=0
∴ x=5
y=32xy+xy分之x²+x
=x(x+1)/x(2+y)
=(x+1)/(2+y)
=(5+1)/(2+3)
=6/5