(x-3)(x²-2)-(x-5)(3-x)-2(3-x)²

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(x-3)(x²-2)-(x-5)(3-x)-2(3-x)²
(x-3)(x²-2)-(x-5)(3-x)-2(3-x)²

(x-3)(x²-2)-(x-5)(3-x)-2(3-x)²
原式=(x-3)(x²-2)+(x-3)(x-5)-(x-3)(2x-6)
=(x-3)[(x²-2)+(x-5)-(2x-6)]
=(x-3)(x²-2+x-5-2x+6)
=(x-3)(x²-x+1)