求∫x-3/x²-2x+2 dx,∫x³/√（4-x²）dx

求∫x-3/x²-2x+2 dx,∫x³/√（4-x²）dx
求∫x-3/x²-2x+2 dx,∫x³/√（4-x²）dx

求∫x-3/x²-2x+2 dx,∫x³/√（4-x²）dx
1,=∫(x-1-2)/((x-1)^2+1)dx
=1/2∫1/((x-1)^2+1)d((x-1)^2+1)-2∫1/((x-1)^2+1)d(x-1)
=1/2ln(x^2-2x+2)-2arctg(x-1)+c
2,=1/2∫((4-x^2)-4)/√（4-x²）d(4-x^2)
=1/3(4-x^2)^3/2-4(4-x^2)^1/2+c