解方程:1/(x+4)+1/(x+7)=1/(x+5)+1/(x+6)我是这样写的(2x+11)/(x+7)(x+4)=(2x+11)/(x+5)(x+6);(x+4)(x+7)=(x+5)(x+6);x2+11x+28=x2+11x+30;我的数学比较烂,但是然后就不知道怎么算了……

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/05 19:36:58
解方程:1/(x+4)+1/(x+7)=1/(x+5)+1/(x+6)我是这样写的(2x+11)/(x+7)(x+4)=(2x+11)/(x+5)(x+6);(x+4)(x+7)=(x+5)(x+6);x2+11x+28=x2+11x+30;我的数学比较烂,但是然后就不知道怎么算了……

解方程:1/(x+4)+1/(x+7)=1/(x+5)+1/(x+6)我是这样写的(2x+11)/(x+7)(x+4)=(2x+11)/(x+5)(x+6);(x+4)(x+7)=(x+5)(x+6);x2+11x+28=x2+11x+30;我的数学比较烂,但是然后就不知道怎么算了……
解方程:1/(x+4)+1/(x+7)=1/(x+5)+1/(x+6)
我是这样写的(2x+11)/(x+7)(x+4)=(2x+11)/(x+5)(x+6);(x+4)(x+7)=(x+5)(x+6);x2+11x+28=x2+11x+30;我的数学比较烂,但是然后就不知道怎么算了……

解方程:1/(x+4)+1/(x+7)=1/(x+5)+1/(x+6)我是这样写的(2x+11)/(x+7)(x+4)=(2x+11)/(x+5)(x+6);(x+4)(x+7)=(x+5)(x+6);x2+11x+28=x2+11x+30;我的数学比较烂,但是然后就不知道怎么算了……
:1/(x+4)+1/(x+7)=1/(x+5)+1/(x+6)
1/(X+4)-1/(X+5)=1/(X+6)-1/(X+7)
(X+5-X-4)/(X²+9X+20)=(X+7-X-6)/(X²+13X+42)
X²+9X+20=X²+13X+42
X=-11/2

-5.5。。。。(好吧 错了不怪我) 要过程的话 我照相找给你哈

应该这样做!
1/(x+4)+1/(x+7)=1/(x+5)+1/(x+6)
两边同乘以(x+4)(x+7)(x+5)(x+6)得
(x+7)(x+5)(x+6)+(x+5)(x+6)(x+4)=(x+4)(x+7)(x+6)+(x+4)(x+7)(x+5)
(x+5)(x+6)[(x+7)+(x+4)]=(x+4)(x+7)[(x+6)+(x+5)]
(x...

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应该这样做!
1/(x+4)+1/(x+7)=1/(x+5)+1/(x+6)
两边同乘以(x+4)(x+7)(x+5)(x+6)得
(x+7)(x+5)(x+6)+(x+5)(x+6)(x+4)=(x+4)(x+7)(x+6)+(x+4)(x+7)(x+5)
(x+5)(x+6)[(x+7)+(x+4)]=(x+4)(x+7)[(x+6)+(x+5)]
(x+5)(x+6)(2x+11)=(x+4)(x+7)(2x+11)
(x+5)(x+6)(2x+11)-(x+4)(x+7)(2x+11)=0
(2x+11)[(x+5)(x+6)-(x+4)(x+7)]=0
2*(2x+11)=0
所以2x+11=0
x=﹣11/2
经检验
x=﹣11/2
是原方程的解

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通分(2x+11)/(x+4)(x+7)=(2x+11)/(x+5)(x+6)(2x+11)[1/(x^2+11x+28)-1/(x^2+11x+30)]=0x^2+11x+28≠x^2+11x+30所以1/(x^2+11x+28)-1/(x^2+11x+30)≠0所以2x+11=0x=-11/2分式方程要检验经检验swaex=-11&#47...

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通分(2x+11)/(x+4)(x+7)=(2x+11)/(x+5)(x+6)(2x+11)[1/(x^2+11x+28)-1/(x^2+11x+30)]=0x^2+11x+28≠x^2+11x+30所以1/(x^2+11x+28)-1/(x^2+11x+30)≠0所以2x+11=0x=-11/2分式方程要检验经检验swaex=-11/2是方程的解

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