作业帮计算[(3x-2y)²-(3x+2y)²+3x²y²]÷2xy
来源：学生作业帮助网 编辑：作业帮 时间：2024/04/29 16:08:47
![计算[(3x-2y)²-(3x+2y)²+3x²y²]÷2xy](/uploads/image/z/568233-9-3.jpg?t=%E8%AE%A1%E7%AE%97%5B%283x-2y%29%26%23178%3B-%283x%2B2y%29%26%23178%3B%2B3x%26%23178%3By%26%23178%3B%5D%C3%B72xy)
计算[(3x-2y)²-(3x+2y)²+3x²y²]÷2xy
计算[(3x-2y)²-(3x+2y)²+3x²y²]÷2xy
计算[(3x-2y)²-(3x+2y)²+3x²y²]÷2xy
原式=（9x^2-12xy+4y^2-9x^2-12xy-4y^2+3x^2y^2)/2xy
=(-24xy+3x^2y^2)/2xy
=-12+3/2*xy
[(3x-2y)²-(3x+2y)²+3x²y²]÷2xy
=(9x²-12xy+4y²-9x²-12xy-4y²+3x²y²)÷2xy
=(-24xy+3x²y²)÷2xy
=-12+3xy/2
[(3x-2y)²-(3x+2y)²+3x²y²]÷2xy
=（9x²-12xy+4y²-9x²-12xy-4y²+3x²y²）÷2xy
=-21xy÷2xy
=-10.5