若|x-1|+|y+2|+|z-3|=0则(x+1)(y-2)(z+3)的值为( ) a.48 b.-48 c.0 d.xyz

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/03 00:36:43
若|x-1|+|y+2|+|z-3|=0则(x+1)(y-2)(z+3)的值为( ) a.48 b.-48 c.0 d.xyz

若|x-1|+|y+2|+|z-3|=0则(x+1)(y-2)(z+3)的值为( ) a.48 b.-48 c.0 d.xyz
若|x-1|+|y+2|+|z-3|=0则(x+1)(y-2)(z+3)的值为( ) a.48 b.-48 c.0 d.xyz

若|x-1|+|y+2|+|z-3|=0则(x+1)(y-2)(z+3)的值为( ) a.48 b.-48 c.0 d.xyz
|x-1|+|y+2|+|z-3|=0
x-1=0
y+2=0
z-3=0
x=1
y=-2
z=3
(x+1)(y-2)(z+3)
=2*(-4)*6
=-48
B

绝对值里面的数字全是大于等于0的 所以得 x=1 y=-2 z=3 所以选b

|x-1|+|y+2|+|z-3|=0
x-1=0 x=1
y+2=0 y=-2
z-3=0 z=3
(x+1)(y-2)(z+3)=2*(-4)*6=-48
选B

b

|x-1|+|y+2|+|z-3| =0;
x-1=0,y+2=0,z-3=0
x=1,y=-2,z=3
(x+1)(y-2)(z+3)=(1+1)(-2-2)(3+3)=2*(-4)*6=-48

|x-1|+|y+2|+|z-3|=0
绝对值、都大于等于0
相加为0则各项均为0
所以x-1=0
y+2=0
z-3=0
所以x=1
y=-2
z=3
所以(x+1)(y-2)(z+3)
=2*(-4)*6
=-48