(4a-1)/[(a+2)(a-1)]=m/(a+2)+n/(a-1),求m,n的值

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(4a-1)/[(a+2)(a-1)]=m/(a+2)+n/(a-1),求m,n的值

(4a-1)/[(a+2)(a-1)]=m/(a+2)+n/(a-1),求m,n的值
(4a-1)/[(a+2)(a-1)]=m/(a+2)+n/(a-1),求m,n的值

(4a-1)/[(a+2)(a-1)]=m/(a+2)+n/(a-1),求m,n的值
m/(a+2)+n/(a-1)=m*(a-1)+n*(a+2)/[(a+2)(a-1)]
4a-1=m*(a-1)+n*(a+2)/=(m+n)a+2n-m
于是 m+n=4 m=4-n
2n-m=-1 2n-4+n=-1 n=1
m=3

m+n=4和2n-m=-1求得m=3,n=1

m=4a/a+2 n=1/1-a