设函数f(x)=1/3a(x^3)+b(x^2)+x+3(a≠0) 1)a,b满足什么条件时,f(x)取得极值?2）已知a＞0,且f(x)在区间（0,1]上单调递增,试用a表示出b的取值范围?

设函数f(x)={a/x+b/(x²-x) x>1{x x 设函数f(x)=-1/3x设函数f(x)=-1/3x 1.设函数f(x)=x^3+a(x²)-9x-1,(a 设函数f(x)=ln(a+x^2) x>1 =x+b x 设函数f(x)=a/(1+x),x≥0；2x+b,x 设函数f(x)=m-√x+3,若存在实数a,b,(a 设函数f(x)=m-根号下x+3,.若存在实数a,b(a 设函数f(x)=m-√x+3,若存在实数a,b,(a 设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0 设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0 设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0 设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0 设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0 设函数f(x)=-1/3x^3+2ax^2-3a^2x+b,0 设a=(2x-6,5x),b=(1/2x,3+x/5),则函数f(x)=a乘b的最小值为? 设函数f(x)=ax+b,其中a,b为实数,f1(x)=f(x),fn+1(x)=f(fn(x)),n=1,2,3…若f7(x)=128x+381,求a+b? 设函数f(x)=ax+b,其中a,b为实数,f1(x)=f(x),fn+1(x)=f(fn(x)),n=1,2,3…若f7(x)=128x+381,求a+b? 设函数f(x)=asin(x)+b (a