(根号2-根号3-根号6)×(根号3-根号2-根号6)请计算,

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(根号2-根号3-根号6)×(根号3-根号2-根号6)请计算,

(根号2-根号3-根号6)×(根号3-根号2-根号6)请计算,
(根号2-根号3-根号6)×(根号3-根号2-根号6)
请计算,

(根号2-根号3-根号6)×(根号3-根号2-根号6)请计算,
(√2-√3-√6)×(√3-√2-√6)
=[-√6+(√2-√3)]×[-√6-(√2-√3)]
=(-√6)^2-(√2-√3)^2
=6-(2-2√6+3) = 1+2√6

=(-根号6)^2 -(根号3-根号2)^2
=6-(3+2-2*根号6)
=1+2*根号6

:(根号2-根号3-根号6)×(根号3-根号2-根号6)
=【(根号2-根号3)-根号6】×{-【(根号2-根号3)+根号6】}
=-【(根号2-根号3)^2-(根号6)^2】
=-【2-2根号6+3-6】
=-(-2根号6-1)
=2根号6+1

=(根号2-根号3-根号6)×(-(根号2-根号3+根号6))
=-(根号2-根号3-根号6)×(根号2-根号3+根号6)
=-(根号2-根号3)平方+6
=-2-3+2*根号6+6
=2*根号6+1

分别提出-1,变形[根6+(根3-根2)]×[根6-(根3-根2)],然后有平方差公示展开得,6-(根3-根2)的平方,得1+2倍根6

如图:

完全平方差啊