若χ-2y=7,χy=3,则2χy-4y+2χ+5=多少

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若χ-2y=7,χy=3,则2χy-4y+2χ+5=多少

若χ-2y=7,χy=3,则2χy-4y+2χ+5=多少
若χ-2y=7,χy=3,则2χy-4y+2χ+5=多少

若χ-2y=7,χy=3,则2χy-4y+2χ+5=多少
2χy-4y+2χ+5
=2χy+2(x-2y)+5
=2×3+2×7+5
=25

2χy-4y+2χ+5=2xy-2(2y-x)+5
xy=3
2y-x=-7
所以2χy-4y+2χ+5=2*3-2(-7)+5=6+14+5=25

2xy-4y+2x+5
=2xy+(4y-2x)+5
=2xy+[-(2X-4y)]+5
=6+(-14)+5
=-3

2χy-4y+2χ+5
=2χy+2(x-2y)+5
=2×3+2×7+5
=25
所以答案是25!

2xy=6
2(x-2y)=14
原式=6+14+5=25