设A,B为n阶矩阵,且满足A^2=A,B^2=B,(A+B)^2=(A+B),证明:AB=0.

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/28 03:32:56
设A,B为n阶矩阵,且满足A^2=A,B^2=B,(A+B)^2=(A+B),证明:AB=0.

设A,B为n阶矩阵,且满足A^2=A,B^2=B,(A+B)^2=(A+B),证明:AB=0.
设A,B为n阶矩阵,且满足A^2=A,B^2=B,(A+B)^2=(A+B),证明:AB=0.

设A,B为n阶矩阵,且满足A^2=A,B^2=B,(A+B)^2=(A+B),证明:AB=0.
A^2=A,B^2=B,
(A+B)^2=(A+B)==>AB+BA=0==>0=A^2B+ABA=AB+ABA,0=ABA+BA^2=ABA+BA
===>ABA=-AB=-BA
==>AB=BA

直接展开就可以

A^2=A,B^2=B,
(A+B)^2=(A+B)==>AB+BA=0==>0=A^2B+ABA=AB+ABA,0=ABA+BA^2=ABA+BA
===>ABA=-AB=-BA
==>AB=BA