分解因式(3)(y+y+1/4 (4)(x-y)²+16(x+y)²

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分解因式(3)(y+y+1/4 (4)(x-y)²+16(x+y)²

分解因式(3)(y+y+1/4 (4)(x-y)²+16(x+y)²
分解因式(3)(y+y+1/4 (4)(x-y)²+16(x+y)²

分解因式(3)(y+y+1/4 (4)(x-y)²+16(x+y)²
A:
(3)Y + Y +1 / 4 =(Y +1 / 2)2
(4)(XY)-16(X + Y)2 = XY + 4 (x + y的)] [XY-4(+ y)的] =(5×3 y)的(-3倍,5年)= - (5×3 y)的(3×5 y)的

答:
(3)y²+y+1/4=(y+1/2)²
(4)(x-y)²-16(x+y)²=[x-y+4(x+y)][x-y-4(x+y)]=(5x+3y)(-3x-5y)=-(5x+3y)(3x+5y)看清楚(x-y)²+16(x+y)²回复:如果是高中的题,可以在复数域分解。 (x-y)²+16(x+y)...

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答:
(3)y²+y+1/4=(y+1/2)²
(4)(x-y)²-16(x+y)²=[x-y+4(x+y)][x-y-4(x+y)]=(5x+3y)(-3x-5y)=-(5x+3y)(3x+5y)

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(3)y²+y+1/4=(y+1/2)²
(4)(x-y)²+16(x+y)²=x²-2xy+y²+16x²+32xy+16y²=17x²+17y²+30xy

答:
(3)Y + Y +1 / 4 =(Y +1 / 2)2
(4)(XY)-16(X + Y)2 = XY +(X + y)的] [XY-4(+ y)的] =(5×3 y)的(-X,5)= - (5×3 y)的(3×5年)

A:
(3)Y + Y +1 / 4 =(Y +1 / 2)2
(4)(XY)-16(X + Y)2 = XY +(X +的y)] [XY-4(+ y)的] =(5×3,Y)(-3倍,5)= - (5×3 Y)(3×5年)