若sin(6分之π-角二法)=a,则cos(3分之2π-角二法)=?

来源:学生作业帮助网 编辑:作业帮 时间:2024/04/29 23:36:52
若sin(6分之π-角二法)=a,则cos(3分之2π-角二法)=?

若sin(6分之π-角二法)=a,则cos(3分之2π-角二法)=?
若sin(6分之π-角二法)=a,则cos(3分之2π-角二法)=?

若sin(6分之π-角二法)=a,则cos(3分之2π-角二法)=?
sin(π/6-α)=a
cos(2π/3-α)=-cos(π-2π/3+α)=-cos(π/3+α)=-cos(π/2-(π/6-α))=-sin(π/6-α)=-a