作业帮【高数】求教神人简化arccos(cos(3x)) 简化式子 f(x)=arccos(cos(3x)) x属于[-π/2,π/2]
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/12 01:57:22
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【高数】求教神人简化arccos(cos(3x)) 简化式子 f(x)=arccos(cos(3x)) x属于[-π/2,π/2]
【高数】求教神人简化arccos(cos(3x))
简化式子 f(x)=arccos(cos(3x)) x属于[-π/2,π/2]
【高数】求教神人简化arccos(cos(3x)) 简化式子 f(x)=arccos(cos(3x)) x属于[-π/2,π/2]
令f(x)=arccos(cos(3x))=t（0=
分段函数
y=|3x| x属于[-π/3,π/3]
y=3x-2/3π x属于[-π/2,-π/3]
y=-3x+2/3π x属于[π/3,π/2]
f(x)=3X+π( x属于[-π/2,-π/6] )
=3x ( x属于[-π/6,π/6] )
=3x-π ( x属于[π/6,π/2] )