式子sin10π/3-根号2cos(-19π/4)-1/2tan(-13π/3)的值是

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式子sin10π/3-根号2cos(-19π/4)-1/2tan(-13π/3)的值是

式子sin10π/3-根号2cos(-19π/4)-1/2tan(-13π/3)的值是
式子sin10π/3-根号2cos(-19π/4)-1/2tan(-13π/3)的值是

式子sin10π/3-根号2cos(-19π/4)-1/2tan(-13π/3)的值是
sin(10π/3)-√2cos(-19π/4)-1/2tan(-13π/3)
=sin(3π+π/3)-√2cos(19π/4)+1/2tan(13π/3)
=sin(3π+π/3)-√2cos(4π+3π/4)+1/2tan(4π+π/3)
=sin(π+π/3)-√2cos(3π/4)+1/2tan(π/3)
=-sin(π/3)-√2cos(3π/4)+1/2tan(π/3)
=-√3/2-√2*(-√2/2)+1/2*√3
=1

式子sin10π/3-根号2cos(-19π/4)-1/2tan(-13π/3)的值是 3.3 式子根号下(1-2sin10度cos10度)/cos10-根号下{1-(cos^2)170度}的值为_____ . 求值sin10π/3-根号2cos(-19π/4)+tan(13π/3) 〔cos40°(cos10°+根号3sin10°)〕/ (2cos^25°-1) 根号(1-2sin10°cos10°)/(cos10°-根号1-cos^2170°) 化简:根号1-2sin10°*cos10°/cos10°-根号1-cos平方170° 根号1-2cos10度sin10度/根号1-cos平方10度-cos370度 已知x∈[0,π/2],求函数y=cos(π/12 - x)-cos(5π/12 + x)的值域?已知函数f(x)=a*sinx+b*cosx,(ab≠0)的最大值是2,且f(π/6)=根号3.求f(π/3)化简:根号【1+sin10°】+根号【1-sin10°】 根号1-2sin10度cos10度 除以sin10度-根号1-sin10度的平方 sin40°*(1-sin10°)/[sin10°*(cos20°)^2]2*根号3 [2sin50°+sin10°(1+根号3tan10°)]乘sin10°等于? (1/sin10°)减(根号2/sin10°)=?(1/sin10°)减[(根号2)/sin10°]=? 计算2cos40度-cot20度cos度-根号3sin10度tan70度.求解过程 [2sin50+sin10(1+根号3tan10)]sin80 1/sin10°-根号3/sin80°原式=1/sin10-√3/cos10 =(cos10-√3sin10)/sin10cos10 =2(1/2cos10-√3/2*sin10)/sin10cos10 =2cos(10+60)/sin10cos10 =4cos70/sin20 =4请将=2(1/2cos10-√3/2*sin10)/sin10cos10 =2cos(10+60)/sin10cos10 写的更细些不明白2 根号下(1-2sin10°cos10°)除以cos10°-根号下(1-cos^2 10°) 1、根号下1-2sin10°*cos10°除以cos10°-根号下1-cos²170° 1/sin10°-根号3/sin80°的值为原式=1/sin10-√3/cos10 =(cos10-√3sin10)/sin10cos10 =2(1/2cos10-√3/2*sin10)/sin10cos10 =2cos(10+60)/sin10cos10 =4cos70/sin20 =4我想问为什么4cos70/sin20 =4,怎么算出来的是2cos(10+60)/sin10cos10 =4cos