x=1:2 和y=x.^2 sum(y) 这是什么意思(matlab)

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x=1:2 和y=x.^2 sum(y) 这是什么意思(matlab)

x=1:2 和y=x.^2 sum(y) 这是什么意思(matlab)
x=1:2 和y=x.^2 sum(y) 这是什么意思(matlab)

x=1:2 和y=x.^2 sum(y) 这是什么意思(matlab)
X取值1,2,和y等于x对应值的平方此时为1,4,sum(y)是y的和即5

matlab小段代码求解释function [R,mx,my,mse]=circle_detect(x,y)N=length(x);a1=2*(sum(x)^2-N*sum(x.*x));a2=2*(sum(x)*sum(y)-N*sum(x.*y));b1=a2;b2=2*(sum(y)^2-N*sum(y.*y));c1=sum(x.*x)*sum(x)-N*sum(x.^3)+sum(x)*sum(y.*y)-N*sum(x.*y.*y);c2=sum(x.*x x=1:2 和y=x.^2 sum(y) 这是什么意思(matlab) Var x=3,y=2; Int I,sum=5; If (x>y) {for (i=1;i sum+=x%2?x: sum(x,y, fun(int x ,int y) {return(x+y);}main() { int a=1,b=2,c=3,sum;sum=fun((a++;b++,a+b),c++);printf(“%d ”,sum);}输出结果是多少? VB编程求前N项和过程y=1+ x^2/(2!)+x^4/(4!)+.x^(2n)/((2n)!)补充代码 y=1+ x^2/(2!)+x^4/(4!)+.x^(2n)/((2n)!)public sub progession(sum#,,eps#)dim n%,t#n=2sum=1t=1do while (abs(t)>=eps)t=sum=sum+tn=loopend subprivate sub form_click()dim p1#call 看看这个lingo程序哪里出错了?model:sets:de/1..8/:x,y;fe/1..5/:f;link(fe,de):W;endsetsdata:x=5 7 5 4 6 5 5 3;y=25 36 32 15 31 28 22 12;L=20;enddatamin=@sum(de:x*w(1,j))+@sum(de:x*w(2,j))+@sum(de:x*w(3,j))+@sum(de:x*w(4,j))+@sum(de:x*w(5,j))+ x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 有关matlab的sum函数问题,其中sum(x,y)的表示方法是什么意思?急用n=10;z = zeros(n,n);cells = z;cells(n/2,.25*n:.75*n) = 1;cells(.25*n:.75*n,n/2) = 1;x = 2:n-1;y = 2:n-1;sum(x,y) = cells(x,y-1) + cells(x,y+1) + ...cells(x-1,y) + c matlab用solve解方程syms x y c en fai;[x,y]=solve('log(y.*(1-x)/(x.*(1-y)))+en','y.*(1-c.*sum((k.*(y./x).^k)/sum(((y./x).*exp(en-2.*pi)).^k)))+x.*c.*sum((k.*(y./x).^k/sum(((y./x)*exp(en-2.*pi)).^k))-fai')Error using ==> solve' log(y.*(1-x)/(x.*(1- VB中赋值语句的有效性下列哪些赋值语句是有效的?sum=sum-sumx+2=x+2x+y=sumlast x+y=1 5x-2y=8 3x-y=7 2x-y=3x表示y和用y表示x (x-2y)(x+y)-2x(-2x-3y)+6x(-x-y),其中x=-1,y=2要讲解和答题 怎么用matlab求m文件中的函数的梯度function sh=fun1(x,m)sh=sum(x.^2)/2*1e6;y=0;for i=1:length(x)y=y+sum(x(1:i));sh=sh+(y-sum(x(1:i))/2)^2*m(i);endend这是fun1的函数,m已知(已赋值),x是长度为24的未知行矩阵,怎么求函 matlab 求亮度 程序,看不懂,function B=Brightness(Y)[m,n,d]=size(Y);b=0;if d==1B=sum(Y(:))/(m*n);endif d==3B(1)=sum(sum(Y(:,:,1)))/(m*n);B(2)=sum(sum(Y(:,:,2)))/(m*n);B(3)=sum(sum(Y(:,:,3)))/(m*n);end lingo模型定义出错问题model: sets: center/1..3/:u; addr/1..7/:v; w(center,addr):x,y;endsets data: y=36 24 49 21 81 72 4530 20 56 24 99 88 5536 24 63 27 90 80 50 ;enddatamin=@sum(w:x(i,j)*y(i,j));@sum(addr:x(1,j))=3;@sum(addr:x(2,j))=2;@sum(a lingo不等式限制条件不起作用model:sets:center/1..3/:u;addr/1..7/:v;w(center,addr):x,y;endsetsdata:y=24 36 21 49 45 72 8120 30 24 56 55 88 9924 36 27 63 50 80 90;enddatamin=@sum(w:x*y);@sum(addr(j):x(1,j))=3;@sum(addr(j):x(2,j))=2;@sum(addr(