作业帮计算: (x-2y+z)(x+2y+z)要过程,谢
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/09 09:10:48
计算: (x-2y+z)(x+2y+z)要过程,谢
计算: (x-2y+z)(x+2y+z)要过程,谢
计算: (x-2y+z)(x+2y+z)要过程,谢
(x-2y+z)(x+2y+z)
=(x+z-2y)(x+z+2y)
=(x+z)²-(2y)²
=x²+2xz+z²-4y²
把前面两项看成一项
(x-2y+z)(x+2y+z)
=[ (x+z)-2y][(x+z)+2y]
=(x+z)^2-(2y)^2
=x^2+2xz+z^2-4y^2
(x-2y+z)(x+2y+z)
=（x+z)^2-4y^2
=x^2+2xz+z^2-4y^2
(x-2y+z)(x+2y+z)=[(x-2y)+z][(x+2y)+z]=(x-2y)*(x+2y)+(x-2y)*z+(x+2y)*z+z^2
=x^2+4y^2+2xz+z^2
平方差公式的运用：（x+z-2y）（x+z+2y）=（x+z）²-（2y）²=x²+2xz+z²-4y²
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